Modification of dictionary returned by locals()¶
ID: py/modification-of-locals Kind: problem Severity: warning Precision: very-high Tags: - reliability - correctness Query suites: - python-security-and-quality.qls
The dictionary returned by
locals() is not a view of the function’s locals, but a copy. Therefore, modification of the dictionary returned from
locals() will not modify the local variables of the function.
If the intention is to modify a local variable, then do so directly.
In this example, rather than assigning to the variable
z directly, the dictionary returned by
locals() is modified.
def modifies_locals_sum(x, y): locals()['z'] = x + y #z will not be defined as modifications to locals() do not alter the local variables. return z def fixed_sum(x, y): z = x + y return z