Member predicate Node :: asDefiningArgument
Gets the argument that defines this DefinitionByReferenceNode, if any.
Unlike Node::asDefiningArgument/0, this predicate gets the node representing
the value of the index’th indirection after leaving a function. For example,
in:
void f(int**);
...
int** x = ...;
f(x);
The node n such that n.asDefiningArgument(1) is the argument x will
contain the value of *x after f has returned, and the node n such that
n.asDefiningArgument(2) is the argument x will contain the value of **x
after the f has returned.
Expr
asDefiningArgument
(
int
index
)